Answer:
53.06°
Step-by-step explanation:
In triangle ABC, since ∠CAB is 90 degree, therefore consider AB to be the opposite and AC be the adjacent.
Now to find the angle, ∠ACB using trigonometry,
tan θ = opposite / adjacent
tan θ = AB / AC
given AC = 6 and AB = 8
tan θ = 8 / 6
tan θ = 1.33
therefore, θ = [tex]tan^{-1}[/tex] 1.33
θ = 53.06°
Therefore, the bearing from post C to post B is 53.06°
