For this case we have that by definition, the equation of a line in the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cut-off point with the y axis
According to the data we have to:
[tex]m = \frac {1} {4}[/tex]
Then, the equation is of the form:
[tex]y = \frac {1} {4} x + b[/tex]
We substitute point (3.0):
[tex]0 = \frac {1} {4} (3) + b\\b = - \frac {3} {4}[/tex]
Finally, the equation is:
[tex]y = \frac {1} {4} x- \frac {3} {4}[/tex]
Answer:
Option B
