A freight car moves along a frictionless level railroad track at constant speed. The car is open on top. A large load of coal is suddenly dumped into the car. What happens to the velocity of the car?

Respuesta :

Answer:

Velocity of the car decreases.

Explanation:

We can understand the situation if we apply the conservation of energy principle to the situation

Let the initial mass of the freight be [tex]m_{f}[/tex]

Initial velocity of the freight be [tex]v_{fi}[/tex]

Thus the initial Kinetic energy of the freight will be [tex]K.E=\frac{1}{2}m_{f}v_{if}^{2}[/tex]

When a Coal Block of mass M falls into the freight it's energy will become

[tex]K.E=\frac{1}{2}(m_{f}+M)v_{ff}^{2}[/tex]

Equating both the energies we get final velocity as[tex]v_{ff}[/tex]

[tex]\frac{1}{2}m_{f}v_{if}^{2}=\frac{1}{2}(M+m_{f})v_{ff}^{2}\\\\v_{ff}=\sqrt{\frac{m_f}{(M+m_{ff})}}\cdot v_{if}[/tex]

As we see that [tex]\sqrt{\frac{m_f}{(M+m_{ff})}}[/tex] is less than 1 we can infer that velocity decreases.