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A dart is thrown horizontally with an initial speed of 12 m/s toward point P, the bull's-eye on a dart board. It hits at point Q on the rim, vertically below P, 0.19 s later. (a) What is the distance PQ? (b) How far away from the dart board is the dart released?

Respuesta :

gilcarusolautaro

Answer:

(a): The distance PQ is  PQ= 0.176 m.

(b): The dart board is d= 2.28 meters away from the point it is released.

Explanation:

Vx= 12 m/s

t= 0.19 s

g= 9.8 m/s²

PQ= g* t²/2

PQ= 0.176 m (a)

d= Vx * t

d=2.28 m  (b)

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