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You are given two resistors, an ammeter, a voltmeter, and a voltage source. By connecting each resistor singly to the voltage source and taking voltage difference and current measurements on the single resistor, you find the following data for each resistor:

Resistor Voltage (V) Current (mA)
1 3.88 43.6
2 4.48 14.45

Using this data, first find the resistance of each resistor and then calculate the following:

(a) The current that would pass through the network of resistors if they were arranged in series and connected to an 7.65 V voltage source.
Iseries =
(b) The current through the circuit if the resistors were arranged in parallel and connected to the same 7.65 V source from part (a).Iparallel =

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evgeniylevi

Try this solution, note, the resistance of each resistor is marked with green colour, the items (a) and (b) - with red colour.

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temdan2001

By using Ohm's law,

a.) Current = 19.17 A

b.) Current = 110.6 A

We are given different voltages and currents for the two resistors.

First resistor:

Voltage [tex]V_{1}[/tex] = 3.88 v

Current [tex]I_{1}[/tex] = 43.6 A

By using Ohm's law, we can calculate [tex]R_{1}[/tex]

V = IR

Make R the subject of formula

R = V/I = 3.88/43.6

R = 0.08899 Ohms

Second resistor

Voltage [tex]V_{2}[/tex] = 4.48 v

Current [tex]I_{2}[/tex] = 14.45 A

By using Ohm's law, we can calculate [tex]R_{2}[/tex]

V = IR

Make R the subject of formula

R = V/I = 4.48/14.45

R = 0.3100 Ohms

a.) Whenever resistors are connected in series, the same current will pass through them

The total resistance in the resistors in series will be achieved by using the below formula

R = [tex]R_{1}[/tex] + [tex]R_{2}[/tex]

R = 0.08899 + 0.3100

R = 0.399 Ohms

By using Ohm's law:

V = IR

Make I the subject of formula

I = V/R = 7.65/0.399

I = 19.17 A

b.) Whenever resistors are arranged in parallel, the same voltage will be supplied to them.

The resultant resistor can be calculated by using the below formula

1/R = 1/[tex]R_{1}[/tex] + 1/[tex]R_{2}[/tex]

1/R = 1/0.08899 + 1/0.3100

1/R = 11.237 + 3.2258

R = 1/14.463

R = 0.069 Ohms

By using Ohm's law,

V = IR

Make I the subject of formula

I = V/R = 7.65/0.069

I = 110.6 A

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