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Enter your answer in the provided box. From the following data, C(graphite) + O2(g) → CO2(g)ΔH o rxn = −393.5 kJ/mol H2(g) + 1 2 O2(g) → H2O(l)ΔH o rxn = −285.8 kJ/mol 2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(l)ΔH o rxn = −3119.6 kJ/mol calculate the enthalpy change for the reaction below: 2 C(graphite) + 3H2(g) → C2H6(g)

Respuesta :

Answer:

final reaction to get is 2C(graphite) + H2(g) → C2H6(g)

First step: 2C(graphite) + 2O2(g) → 2CO2 (g)   ΔH = (-393.5 x 2)

3H2(g) + 3/2O2(g) → 3H2O(l)  ΔH = (-285.8 x 3)

2CO2(g) + 3H2O(l) → C2H6(g) + 7/2O2(g)  ΔH = (-3119.6 X -1/2)

Second step: 2C(graphite) + 2O2(g) + 3H2(g) + 3/2O2 (g) + 2CO2(g) + 3H2O(l) → 2CO2(g) + 3H2O(l) + C2H6(g) + 7/2O2(g)

Third step: 2C(graphite) + O2(g) → C2H6(g)

ΔH final = (-393.5 x 2) + (-285.8 x 3) + (-3119.6 x -1/2) = -84.6 KJ/mol

Explanation: Using Hess Law

In the first step, rearrange the 3 given reactions in a way that they match the final reaction by multiplying or dividing (also the ΔH) by a given number and by reverse (if so the multiply by -1).

In the second step, add all 3 reactions with reactant on their side and product on theirs.

In 3rd step, cancel out similarity in the product and reactant(such as there are (2+3/2 = 7/2)O2 which cancels with 7/2O2 in the product) .

finally, add all 3 ΔH to find the final one which is -84.6 KJ/mol

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