A 0.5775−g sample of solid magnesium is burned in a constant-volume bomb calorimeter that has a heat capacity of 3024 J/°C. The temperature increases by 4.729°C. (a) Calculate the heat associated with the burning Mg in kJ/g. kJ/g (b) Calculate the heat associated with the burning of Mg in kJ/mol. kJ/mol

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Tringa0 Tringa0 · Answer 1 · 2019-07-30T09:01:10+02:00

Answer:

The heat associated with the burning Mg is 24.76 kJ/g.

The heat associated with the burning Mg is 595.85 kJ/mol.

Explanation:

Heat capacity of bomb calorimeter = C = 3024 J/°C

Change in temperature of bomb calorimeter = ΔT=4.729°C

Heat gained by calorimeter = Q

[tex]Q=C\times \Delta T=3024 J/^oC\times 4.729^oC=14,300.496 J=14.300 kJ[/tex]

Mass of magnesium burnt = 0.5775 g

Moles of magnesium = [tex]\frac{0.5775 g}{24 g/mol}=0.0240 mol[/tex]

0.5775 grams of magnesium on burning produces 14.300 kJ.

Then 1 gram of magnesium will produce:

[tex]\frac{14.300 kJ}{0.5775 }=24.76 kJ[/tex]

The heat associated with the burning Mg is 24.76 kJ/g.

0.0240 moles of magnesium on burning produces 14.300 kJ.

Then 1 molof magnesium will produce:

[tex]\frac{14.300 kJ}{0.0240 }=595.85 kJ[/tex]

The heat associated with the burning Mg is 595.85 kJ/mol.