contestada

A rescue plane flying horizontally at spots a survivor in the ocean directly below and releases an emergency kit with a parachute. Because of the shape of the parachute, it experiences insignificant horizontal air resistance. If the kit descends with a constant vertical acceleration of how far away from the survivor will it hit the waves?

Respuesta :

Answer:

It covers a distance of [tex]D_{H}=u_{h}\times \sqrt{\frac{2H}{g}}[/tex] where symbols have the usual meanings.

Explanation:

As shown in the figure

Let the height of aircraft be H meters above ground

Let it's horizontal flying velocity be [tex]v_{f}[/tex]

Using second equation of motion we can find the time it takes for the packet to reach the ground.

We have

[tex]H=ut+\frac{1}{2}gt^{2}\\\\t=\sqrt{\frac{2H}{g}}\because (u=0)[/tex]

Thus horizantal distance covered in this time = [tex]speed\times velocity[/tex] Since there is no horizantal accleration

Thus horizantal distance it covers =[tex]D_{H}=u_{h}\times \sqrt{\frac{2H}{g}}[/tex]

Ver imagen A1peakenbe

Otras preguntas