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I need help please.
In triangle ABC, A = 35°, a = 20, and b = 32. Find B. impossible to tell 21° 33° 67°

Respuesta :

Answer:

The measure of angle B is [tex]67\°[/tex]

Step-by-step explanation:

we know that

Applying the law of sines

[tex]\frac{a}{sin(A)}=\frac{b}{sin(B)}[/tex]

we have

[tex]a=20\ units[/tex]

[tex]b=32\ units[/tex]

[tex]A=35\°[/tex]

substitute the given values and solve for B

[tex]\frac{20}{sin(35\°)}=\frac{32}{sin(B)}[/tex]

[tex]sin(B)=(32)sin(35\°)/20[/tex]

[tex]B=arcsin((32)sin(35\°)/20)[/tex]

[tex]B=67\°[/tex]