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The volume of a sample of hydrogen gas was decreased from 12.16 L to 5.45 L at constant temperature. If the final pressure exerted by the hydrogen gas sample was 5.09 atm, what pressure did the hydrogen gas exert before its volume was decreased?

Respuesta :

Answer : The pressure of the hydrogen gas exert before its volume was decreased will be, 2.28 atm

Explanation :

According to the Boyle's law, the pressure of the gas is inversely proportional to the volume of the gas at constant temperature of the gas and the number of moles of gas.

[tex]P\propto \frac{1}{V}[/tex]

or,

[tex]PV=k[/tex]

or,

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1[/tex] = initial pressure of the gas = ?

[tex]P_2[/tex] = final pressure of the gas = 5.09 atm

[tex]V_1[/tex] = initial volume of the gas = 12.16 L

[tex]V_2[/tex] = final volume of the gas = 5.45 L

Now put all the given values in this formula, we get the initial pressure of the gas.

[tex]P_1\times 12.16L=5.09atm\times 5.45L[/tex]

[tex]P_1=2.28atm[/tex]

Therefore, the pressure of the hydrogen gas exert before its volume was decreased will be, 2.28 atm

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