Answer:
The factors are (3x+1)(2x+1)
Step-by-step explanation:
The expression is:
6x^2 + 5x + 1
We have to break the middle term to find its factors. For this first we have to multiply the coefficient of 1st terms with the constant term:
6*1 = 6
Now we have to find any two numbers whose product is 6 and whose sum is the middle term:
3*2=6
3+2=5
Now break the middle term by these two numbers.
6x^2 + 5x + 1
6x^2+3x+2x+1
Group the first two terms and last two terms:
(6x^2+3x)+(2x+1)
Now take out common factor from each term:
3x(2x+1)+1(2x+1)
(3x+1)(2x+1)
Therefore the factors are (3x+1)(2x+1)....
Answer:
(2x + 1)(3x + 1)
Step-by-step explanation:
Given
6x² + 5x + 1
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 6 × 1 = 6 and sum = + 5
The factors are + 3 and + 2
Use these factors to split the x0 term
6x² + 3x + 2x + 1 ( factor the first/second and third/fourth terms )
= 3x(2x + 1) + 1 (2x + 1) ← factor out (2x + 1) from each term
= (2x + 1)(3x + 1) ← in factored form
