Answer:
s = 23.72 m
v = 21.56 m/s² Â
Explanation:
given
time to reach the ground (t) = 2.2 second
we know that
a) s = u t + 0.5 g t²
  u = 0 m/s
  g = 9.8 m/s²
  s = 0 + 0.5 × 9.8 × 2.2²
 s = 23.72 m
b) impact velocity
   v = √(2gh)
   v = √(2× 9.8 × 23.72)  Â
   v =  √464.912
   v = 21.56 m/s² Â