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BASEBALL IN SPACE baseball in space You are observing a baseball in space, with mass m = 0.145 kg. It is moving past your spacecraft with speed v = 22.9 m/sec, to the north. Your Acme Tractor Beam can exert 1.3 Newtons of pull force on that baseball. CALCULATE: How long will it take your Acme Tractor Beam to slow down the baseball to a stop? Enter the numeric part of your answer, to the nearest hundredth of a second, i.e., 0.01 sec. E.g., if your answer is 60.5329 sec, then type in 60.53 in the answer box.

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jelimarlm

Answer:

It takes 2.55 sec

Explanation:

First we need to find the aceleration with this equation:

F = m*a

[tex]a = \frac{F}{m}[/tex]

Where:   F = 1.3 Newtons

              m = 0.145 kg

Then      [tex]a = \frac{1.3 Newtons}{0.145 kg}[/tex]

              [tex]a = 8.9655 m/sec^{2}[/tex]

Now we are ready to calculate the time with the next equation:

[tex]V_{f} = V_{o} + a*t[/tex]

[tex]V_{f} - V_{o} = a*t[/tex]

[tex]t = \frac{V_{f} - V_{o}}{a}[/tex]

Where:   [tex]V_{o} = 22.9 m/sec[/tex]   (at the beginning)

              [tex]V_{f} = 0 m/sec[/tex]   (at the end because it stops)

We must use [tex]a = - 8.9655 m/sec^{2}[/tex]   because in this case speed is decreasing

Finally:   [tex]t = \frac{0 m/sec - 22.9 m/sec}{- 8.9655 m/sec^{2} }[/tex]

              t = 2.55 sec

onyebuchinnaji

The time taken for the tractor to slow down the baseball is 2.55 s.

The given parameters;

  • mass of the baseball, m = 0.145 kg
  • velocity of the spacecraft, v = 22.9 m/s
  • force exerted by the tractor, F = 1.3 N

The acceleration of the baseball is calculated as follows;

F = ma

[tex]a = \frac{F}{m} \\\\a = \frac{1.3}{0.145} \\\\a = 8.966 \ m/s^2[/tex]

The time taken for the tractor to slow down the baseball is calculated as follows;

v = u + at

v = 0 + at

v = at

[tex]t = \frac{22.9}{8.966} \\\\t = 2.55 \ s[/tex]

Thus, the time taken for the tractor to slow down the baseball is 2.55 s.

Learn more here:https://brainly.com/question/2018532

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