[tex]\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$1000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ t=years\dotfill &10 \end{cases} \\\\\\ A=1000e^{0.08\cdot 10}\implies A=1000e^{0.8}\implies A=2225.54~\hfill \stackrel{interest = A - P}{1225.54}[/tex]
btw, we could have used the compound formula just the same, by simply using a compounding cycle of 365, namely daily, assuming a year has 365 days.
