Answer:
(14.7 , 16.9)
Step-by-step explanation:
it is given that [tex]\bar{x}=15.8[/tex] tons
σ=3.8 tons
n=49
at 95% confidence level α=1-.95=0.05
[tex]z_\frac{\alpha }{2}=z_\frac{0.05}{2}=z_{0.025}\\[/tex]
=1.96 ( from the standard table)
at 95% confidence level the coefficient interval for μ is
[tex]\bar{x}\pm z_\frac{\alpha }{2}\times \frac{\sigma }{\sqrt{n}}[/tex]
[tex]15.8\pm 1.96\times \frac{3.8}{ \sqrt{49}}[/tex]
[tex]15.8\pm 1.1[/tex]
(14.7, 16.9)
