Answer: 0.965
Step-by-step explanation:
Given : Water use in the summer is normally distributed with
[tex]\mu=311.4\text{ million gallons per day}[/tex]
[tex]\sigma=40 \text{ million gallons per day}[/tex]
Let X be the random variable that represents the quantity of water required on a particular day.
Z-score : [tex]\dfrac{x-\mu}{\sigma}[/tex]
[tex]\dfrac{350-311.4}{40}=0.965[/tex]
Now, the probability that a day requires more water than is stored in city reservoirs is given by:-
[tex]P(x>350)=P(z>0.965)=1-P(z<0.965)[/tex]
We can see that on comparing the above value to the given P(X > 350)= 1 - P(Z < b) , we get the value of b is 0.965.