Answer: 2.632
Step-by-step explanation:
Given : The probability that the population has a particular genetic mutation = 1 % = 0.01
Let X be a random variable representing the number of people with genetic mutation in a group of 700 people.
Now, X follows the binomial distribution with parameters:
[tex]n=700;\ p=0.01[/tex]
The standard deviation for binomial distribution is given by :-
[tex]\sigma=\sqrt{np(1-p)}\\\\=\sqrt{700\times0.01(1-0.01)}\\\\=2.6324893162\approx2.632[/tex]
Hence, the standard deviation = 2.632
