Explanation:
Given that,
Terminal voltage = 3.200 V
Internal resistance [tex]r= 5.00\ \Omega[/tex]
(a). We need to calculate the current
Using rule of loop
[tex]E-IR-Ir=0[/tex]
[tex]I=\dfrac{E}{R+r}[/tex]
Where, E = emf
R = resistance
r = internal resistance
Put the value into the formula
[tex]I=\dfrac{3.200}{1.00\times10^{3}+5.00}[/tex]
[tex]I=3.184\times10^{-3}\ A[/tex]
(b). We need to calculate the terminal voltage
Using formula of terminal voltage
[tex]V=E-Ir[/tex]
Where, V = terminal voltage
I = current
r = internal resistance
Put the value into the formula
[tex]V=3.200-3.184\times10^{-3}\times5.00[/tex]
[tex]V=3.18\ V[/tex]
(c). We need to calculate the ratio of the terminal voltage of voltmeter equal to emf
[tex]\dfrac{Terminal\ voltage}{emf}=\dfrac{3.18}{3.200 }[/tex]
[tex]\dfrac{Terminal\ voltage}{emf}= \dfrac{159}{160}[/tex]
Hence, This is the required solution.
