Answer:
-$ 0.79
Step-by-step explanation:
Since, the player has made 282 out of 393 free throws,
So, the probability of a free throw = [tex]\frac{282}{393}[/tex],
Thus, the probability of 2 free throws = [tex]\frac{282}{393}\times \frac{282}{393}=\frac{8836}{17161}[/tex]
And, the probability of not getting 2 free throws = [tex]1-\frac{8836}{17161}=\frac{8325}{17161}[/tex]
Given, the price of winning ( getting 2 free throws ) is $6 while the price of losing ( not getting 2 free throws ) is - $ 8 ( ∵ there is a loss of $ 8 ),
Hence, the expected value of the proposition = probability of winning × winning value + probability of losing × losing value
[tex]= \frac{8836}{17161}\times 6 + \frac{8325}{17161}\times -8[/tex]
[tex]=\frac{53016}{17161}-\frac{66600}{17161}[/tex]
[tex]=-\frac{13584}{17161}[/tex]
[tex]=-\$ 0.79156226327[/tex]
[tex]\approx -\$ 0.79[/tex]