Given:
Sample 1:
Chloroform is [tex]CHCl_{3}[/tex]
12 g Carbon
1.01 g Hydrogen
106.4 g Cl
Sample 2:
30.0 g of Carbon
Solution:
mass of chloroform from sample 1:
12 + 1.01 +106.4 =119.41 g
Now, for the total mass of chloroform in sample 2:
mass of chloroform [tex]\times[/tex][tex]\frac{given mass of carbon}{mass of carbon atom}[/tex]
mass of chloroform = 119.41 [tex]\times[/tex][tex]\frac{30}{12}[/tex] = 298.53 g
