Answer:
Tangential Speed equals 5.57m/s
Explanation:
In the figure shown for equilibrium along y- axis we have
[tex]\sum F_{y}=0[/tex]
Resolving Forces along y axis we have
[tex]Tcos(\theta )=mg............(i)[/tex]
Similarly along x axis
[tex]\sum F_{x}=ma_{x}[/tex]
[tex]Tsin(\theta )=m[tex]\frac{v^{2} }{r}[/tex]............(ii)[/tex]
Dividing ii by i we have
[tex]tan(\theta )=\frac{v^{2}}{rg}[/tex]
In the figure below we have [tex]r=lsin(\theta )[/tex]
Thus solving for v we have
[tex]v=\sqrt{lgsin(\theta) tan(\theta )}[/tex]
Applying values we get
v=5.576m/s
