Transform M to the standard normally distributed random variable Z via
[tex]Z=\dfrac{M-\mu_M}{\sigma_M}[/tex]
where [tex]\mu_M[/tex] and [tex]\sigma_M[/tex] are the mean and standard deviation for [tex]M[/tex], respectively. Then
[tex]P(236.5<M<236.7)=P(-0.2308<Z<-0.0769)\approx\boxed{0.0606}[/tex]
Answer:
0.0606. Β Β Β Β Β Β Β Β Β Β Β Β . Β Β Β Β Β Β Β Β
hope this helps