Respuesta :
Answer:
molar mass of nicotine will be 162.16g/mol
Explanation:
The mass of nicotine taken = 0.60g
The volume of solution = 12mL
the osmotic pressure of solution = 7.55 atm
Temperature in kelvin =298.15K (25+ 273.15)
The formula which relates osmotic pressure and concentration (moles per L) is:
Ï€ = MRT
Where
Ï€ = osmotic pressure (unit atm) = 7.55 atm
M = molarity (mol /L)
T= temperature = (K) = 298.15 K
R = gas constant = 0.0821 L atm /mol K
Putting values
[tex]7.55=MX0.0821X298.15[/tex]
Therefore
[tex]M=\frac{7.55}{0.0821X298.15}=0.308\frac{mol}{L}[/tex]
Molarity is moles of solute dissolve per litre of solution
The volume of solution in litre = 0.012 L
[tex]molarity=\frac{moles}{V}[/tex]
[tex]moles=molarityXvolume=0.308X0.012=0.0037mol[/tex]
we know that
[tex]moles=\frac{mass}{ymolarmass}[/tex]
molar mass = [tex]\frac{mass}{moles}=\frac{0.60}{0.0037}=162.16\frac{g}{mol}[/tex]
