A ray of light traveling in air is incident on the flat surface of a piece of glass at an angle of 65.9° with respect to the normal to the surface of the glass. If the ray refracted into the glass makes an angle of 34.8° with respect to the normal, what is the refractive index of the glass?

Respuesta :

Answer:

[tex]n_{glass}[/tex] = 1.6

Explanation:

[tex]\theta _{i}[/tex] = Angle of incidence = 65.9°

[tex]\theta _{r}[/tex] = Angle of refraction = 34.8°

[tex]n_{air}[/tex] = Index of refraction of air = 1

[tex]n_{glass}[/tex] = Index of refraction of glass = ?

Using Snell's law

[tex]n_{air}[/tex] Sin[tex]\theta _{i}[/tex] = [tex]n_{glass}[/tex] [tex]\theta _{r}[/tex]

(1) Sin65.9 =  [tex]n_{glass}[/tex] Sin34.8

[tex]n_{glass}[/tex] = 1.6

Since the index of refraction of air is 1, the refractive index of the glass is 1.6 approximately

Refractive Index

Refractive Index is the measure of refraction or bending when light passes from one medium to another.

Given that a ray of light traveling in air is incident on the flat surface of a piece of glass at an angle of 65.9° with respect to the normal to the surface of the glass. If the ray refracted into the glass makes an angle of 34.8° with respect to the normal, the refractive index of the glass can be calculated with the formula below

n = sin i / sin r

Where

  • n = refractive index
  • i = angle of incidence
  • r = angle of refraction

Substitute all the parameters

n = sin 65.9 / sin 34.8

n = 0.913 / 0.5707

n = 1.599

n = 1.6 approximately

Therefore, the refractive index of the glass is 1.6 approximately.

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