Answer:
50.4 Hz
Explanation:
A = amplitude of the wave = 5 cm = 0.05 m
ÎĽ = linear mass density = 0.04 kg/m
P = maximum power delivered by source = 275 Watt
T = tension force in the string = 121 N
Speed of the wave is given as
[tex]v=\sqrt{\frac{T}{\mu }}[/tex]
[tex]v=\sqrt{\frac{121}{0.04 }}[/tex]
[tex]v[/tex] = 55 m/s
maximum power is given as
[tex]P = \frac{\mu (2\pi f)^{2} A^{2}v}{2}[/tex]
[tex]275 = \frac{(0.04) (2(3.14) f)^{2} (0.05)^{2}(55)}{2}[/tex]
[tex]f[/tex] = 50.4 Hz
