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Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation?
O 1-6 - 751, - 6 + V51)
O 1-6 - 121, -6 + V21)
O 16 - 151,6 + V51)
O (6 - 121,6 + V21)

Respuesta :

chickennoodlesoup180

Answer:

(6-[tex]\sqrt{21}[/tex])  (6+[tex]\sqrt{21}[/tex])

Step-by-step explanation:

khuranashilpa76

The solution set of the equation  x2 = 12x – 15 is O (6 - 121,6 + V21).

The answer is option D.

What is a quadratic equation?

  • A quadratic equation is an equation that can be rearranged in standard form.  

                                 ax²+bx²+c=0

  • The solution gives two values of the single variable.
  • The values are real root and non-real roots.

Calculation

equation x2 = 12x - 15

can be written as

    x² - 12x = -15

On square by adding (-b/2)2 on both sides of the equation

     x²- 12x + (-12/2)² = -15 + (-12/2)²

We get

 ⇒ x² - 12x + (-6)² = -15 + (-6)²

  ⇒  x²- 12x + 36 = -15 + 36

    ⇒  (x - 6)2 = 21

    Taking square root on both sides

⇒x - 6 = ± √21

⇒x - 6 = √21 and x - 6 = - √21

⇒x = (6 + √21 ) and x = (6 - √21)

Learn more about quadratic equations here:-https://brainly.com/question/1214333

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