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A thin coil has 16 rectangular turns of wire. When a current of 3 A runs through the coil, there is a total flux of 4 × 10-3 T·m2 enclosed by one turn of the coil (note that , and you can calculate the proportionality constant ). Determine the inductance in henries.

Respuesta :

Answer:

The inductance is 0.021 H.

Explanation:

Given that,

Number of turns = 16

Current = 3 A

Total flux [tex]\phi=4\times10^{-3}\ Tm^2[/tex]

We need to calculate the inductance

Using formula of total flux

[tex]N\phi = Li[/tex]

[tex]L=\dfrac{N\phi}{i}[/tex]

Where, i = current

N = number of turns

[tex]\phi[/tex] = flux

Put the value into the formula

[tex]L=\dfrac{16\times4\times10^{-3}}{3}[/tex]

[tex]L=0.021\ H[/tex]

Hence, The inductance is 0.021 H.

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