Respuesta :
[tex]\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ y=-2(x-\stackrel{h}{3})^2+\stackrel{k}{4}\qquad\qquad \stackrel{vertex}{(\underline{3},4)}\qquad \qquad \stackrel{\textit{axis of symmetry}}{x=\underline{3}}[/tex]
From the equation of the parabola in vertex-form, it's line of symmetry is given by:
[tex]l: x = 3[/tex]
The equation of a parabola of vertex (h,k) is given by:
[tex]y = a(x - h)^2 + k[/tex]
The line of symmetry is given by:
[tex]l: x = h[/tex]
In this problem, the parabola is modeled by the following equation:
[tex]y = -2(x - 3)^2 + 4[/tex]
Hence, the coefficients of the vertex are [tex]h = 3, k = 4[/tex], and the line of symmetry is:
[tex]l: x = 3[/tex]
A similar problem is given at https://brainly.com/question/24737967
