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A light ray incident on a block of glass makes an incident angle of 50.0° with the normal to the surface. The refracted ray in the block makes an 27.7° with the normal. What is the index of refraction of the glass?

Respuesta :

Answer:

[tex]n_{glass} = 1.65[/tex]

Explanation:

As we know that the angle of incidence is given as

[tex]i = 50.0^o[/tex]

also we have angle of refraction as

[tex]r = 27.7^o[/tex]

now by Snell's law we know that

[tex]n_{air} sin i = n_{glass} sin r[/tex]

[tex]1 sin50 = n_{glass} sin 27.7[/tex]

now we have

[tex]n_{glass} = \frac{sin 50}{sin 27.7}[/tex]

[tex]n_{glass} = 1.65[/tex]

Eduard22sly

The index of refraction of the glass block in which a ray of light with an incident angle of 50° is refracted at an angle of 27.7° is 1.65

Snell's law

index of refraction (n) = Sine i / Sine r

n = Sine i / Sine r

Where

  • i is the angle of incidence
  • r is the angle of refraction

How to determine the refractive index

From the question given above, the following data were obtained:

  • Angle of incidence (i) = 50°
  • Angle of refraction (r) = 27.7°
  • Index of refraction (n) =?

n = Sine i / Sine r

n = Sine 50 / Sine 27.7

n = 1.65

Thus, the index of refraction of the glass block is 1.65

Learn more about Snell's law:

https://brainly.com/question/25758484

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