Please Help Keep getting 6.4

Answer:
r = 3
Step-by-step explanation:
x^2 + 6x + y^2 - 8y = - 16
Take half the linear term and square it.
x^2 + 6x + (3)^2 + y^2 - 8y + (-4)^2 = - 16
Add the squared amounts to the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = - 16 + 9 + 16
Combine on the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = 9
Represent the 2 quadratics as perfect squares.
(x + 3)^2 + y - 4)^2 = 9
The radius is the square root of 9 which is 3
Answer:
radius=3
Step-by-step explanation:
Given:
x^2 +6x +y^2 - 8y=-16
completing the squares
: x^2 +6x +9 = (x+3)^2
:y^2-8y+16 = (y-4)^2
(x+3)^2 + (y-4)^2 -9-16=-16
(x+3)^2 + (y-4)^2=-16+9+16
(x+3)^2 + (y-4)^2=9
Now comparing with standard equation of circle i.e. (x-h)^2 + (y-k)^2=r^2, we get
origin(h,k)= (-3,4)
r=3 !