Answer:
Explanation:
Let
The cylinder imparts an upward velocity which is v m/s which slips on the rod OA.
The distance from the fixed hydraulic cylinder to the collar is given as s
From the figure given below, we can find the resulting angular velocity ω of the link OA in terms of velocity v, the displacement s of point B and the fixed distance d from the given mechanism.
We know that for angular velocity of link OA
[tex]\omega _{OA}=\frac{v\times d}{s^{2}+d^{2}}[/tex]
where v is velocity
s is the displacement
d is the distance
