The game of blackjack played with one​ deck, a player is initially dealt 2 different cards from the 52 different cards in the deck. A winning​ "blackjack" hand is won by getting 1 of the 4 aces and 1 of 16 other cards worth 10 points. The two cards can be in any order. Find the probability of being dealt a blackjack hand. What approximate percentage of hands are winning blackjack​ hands?

Respuesta :

Answer:

a) The probability of being dealt a blackjack hand

[tex]= \frac{64}{1326}[/tex]

b) Approximate percentage of hands winning blackjack​ hands

[tex]4.827%[/tex]

Step-by-step explanation:

It is given that -

Winning Black Jack means -  getting 1 of the 4 aces and 1 of 16 other cards worth 10 points

Thus, in order to win a "black jack" , one is required to pull 1 ace and 1 of 16 other cards

Number of ways in which an ace card can be drawn from a set of 4 ace card is [tex]C^4_1[/tex]

Number of ways in which one card can be drawn from a set of other 16 card is [tex]C^16_1[/tex]

Number of ways in which two cards are drawn from a set of 52 cards is [tex]C^52_2[/tex]

probability of being dealt a blackjack hand

[tex]= \frac{C^4_1* C^16_1}{C^52_2} \\= \frac{4*16}{\frac{51*52}{2} }\\ = \frac{64}{1326} \\[/tex]

Approximate percentage of hands  winning blackjack​ hands

[tex]= \frac{64}{1326} * 100\\= 4.827[/tex]%