Answer:
It is a solution
Step-by-step explanation:
Check and see if (0,0) satisfies both inequalities.
The first inequality is:
[tex]y \geqslant {x}^{2} + x - 4 [/tex]
When we put x=0, and y=0, we get:
[tex]0\geqslant {0}^{2} + 0 - 4[/tex]
[tex] \implies0\geqslant- 4[/tex]
This part is true.
The second inequality is:
[tex]y \leqslant {x}^{2} + 2 x + 1[/tex]
We put x=0 and y=0 to get:
[tex]0 \leqslant {0}^{2} + 2 (0) + 1[/tex]
[tex]0 \leqslant 1[/tex]
This part is also true.
Since the (0,0) not satisfy both, inequalities, it is a solution.
