Simplify (Y^2+7y+6)/(6y^2-6)

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kudzordzifrancis kudzordzifrancis · Answer 1 · 2019-07-25T21:36:41+02:00

Answer:

[tex]\frac{y + 6}{6(y - 1)} [/tex]

Step-by-step explanation:

The given expression is

[tex] \frac{ {y}^{2} + 7y + 6}{6 {y}^{2} - 6} [/tex]

The numerator is a quadratic trinomial and the denominator is different of two squares when 6 is factored.

We factor both the numerator and the denominator to obtain;

[tex] \frac{ (y + 6)(y + 1) }{6(y - 1)(y + 1)} [/tex]

Cancel out the common factors to get:

[tex] \frac{y + 6}{6(y - 1)} [/tex]

This is the simplest form since, we cannot simplify this further.

carlosego carlosego · Answer 2 · 2019-07-25T21:41:34+02:00

For this case we must simplify the following expression:

[tex]\frac {y ^ 2 + 7y + 6} {6y ^ 2-6}[/tex]

We factor the numerator, looking for two numbers that when multiplied by 6 and when added together give 7. These numbers are +6 and +1.

Then, rewriting the expression:

[tex]\frac {(y + 6) (y + 1)} {6 (y ^ 2-1)} =[/tex]

We rewrite the denominator:

[tex]\frac {(y + 6) (y + 1)} {6 (y + 1) (y-1)} =[/tex]

We simplify similar terms:

[tex]\frac {(y + 6)} {6 (y-1)}[/tex]

Answer:

[tex]\frac {(y + 6)} {6 (y-1)}[/tex]