Respuesta :
Answer:
So the probability that the city won't receive rain on none of these days is [tex]\frac{2}{15}[/tex]
Step-by-step explanation:
From the question we know that the probability of rain on June 1 is [tex]\frac{1}{2}[/tex], on July 1 is [tex]\frac{1}{5}[/tex] and in August 1 is [tex]\frac{2}{3}[/tex], So the probability of no rain at any of these days is calculate as:
For June 1:
[tex]P(no-rain)=1-\frac{1}{2} =\frac{1}{2}[/tex]
For July 1:
[tex]P(no-rain)=1-\frac{1}{5} =\frac{4}{5}[/tex]
For August 1:
[tex]P(no-rain)=1-\frac{2}{3} =\frac{1}{3}[/tex]
So the probability that the city won't receive rain on none of these days is the multiplication of the probabilities of no rain for every one of these days. Then:
[tex]P=\frac{1}{2} *\frac{4}{5} *\frac{1}{3} =\frac{4}{30}[/tex]
Simplified the value of P, we obtain: [tex]P=\frac{2}{15}[/tex]
