Respuesta :

ANCKPOP

Answer:

x = 5

Step-by-step explanation:

the expression is "undefined"  when the denominator is equal to zero

  • [tex]\frac{\left(5+x\right)}{25-x^2\:} \\[/tex]

denominator =  25 - x²

Values of x where the equation is "undefined"

0 = 25 - x²

x² = 25

√x² = √25

x = ± 5

Nonnegative value of x where the equation is "undefined"

x = 5

MrRoyal

An expression is said to be undefined, if it has 0 as its denominator. For [tex]\frac{5 + x}{25 - x^2}[/tex] to be undefined, x must be 5.

Given that:

[tex]\frac{5 + x}{25 - x^2}[/tex]

For the expression to be undefined, the denominator must equal 0.

i.e.

[tex]25 - x^2 = 0[/tex]

Collect like terms

[tex]-x^2 = 0 - 25[/tex]

[tex]-x^2 = - 25[/tex]

Cancel out negatives

[tex]x^2 = 25[/tex]

Take positive square root

[tex]x = 5[/tex]

This means that when [tex]x = 5[/tex],  [tex]\frac{5 + x}{25 - x^2}[/tex] is undefined.

Read more about undefined expressions at:

https://brainly.com/question/13464119

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