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Thirty-five more than the limit of weight (w) in an elevator is greater then 1,050 pounds.

A. Model with an inequality.

B. Solve the inequality.

C. Where would the solution for the inequality be graphed on the number line?

Thirtyfive more than the limit of weight w in an elevator is greater then 1050 pounds A Model with an inequality B Solve the inequality C Where would the soluti class=

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Answer:

Part A) [tex]w+35 > 1,050[/tex]

Part B) [tex]w > 1,015\ pounds[/tex]

Part C) The graph in the attached figure

Step-by-step explanation:

Part A) Model with an inequality.

Let

w -----> the limit of weight in an elevator

we know that

The inequality that represent this situation is

[tex]w+35 > 1,050[/tex]

Part B)   Solve the inequality

[tex]w+35 > 1,050[/tex]

solve for w

Subtract 35 sides

[tex]w+35-35 > 1,050-35[/tex]

[tex]w > 1,015\ pounds[/tex]

All real numbers greater than 1,015 pounds

Part C) Where would the solution for the inequality be graphed on the number line?

[tex]w > 1,015\ pounds[/tex]

The solution is the interval -------> (1,015,∞)

In a number line is the shaded area at right of the number x=1.015 (open circle)

see the attached figure

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