Respuesta :
Answer :
(a) The concentration of hydrogen ion and hydroxide ion are, [tex]1.708\times 10^{-7}M[/tex].
(b) The pH of pure water is, 6.78
(c) The pH of solution is, 13
Explanation :
(a) First we have to calculate the concentration of hydrogen ion and hydroxide ion.
As we know that,
[tex]K_w=[H^+][OH^-][/tex]
In pure water, the concentration of hydrogen ion and hydroxide ion are equal. So, let the concentration of hydroxide ion and hydrogen ion be, 'x'.
[tex]2.92\times 10^{-14}=(x)\times (x)[/tex]
[tex]2.92\times 10^{-14}=(x)^2[/tex]
[tex]x=1.708\times 10^{-7}M[/tex]
The concentration of hydrogen ion and hydroxide ion are, [tex]1.708\times 10^{-7}M[/tex].
(b) Now we have to calculate the pH of pure water.
[tex]pH=-\log [H^+][/tex]
[tex]pH=-\log (1.708\times 10^{-7})[/tex]
[tex]pH=6.78[/tex]
The pH of pure water is, 6.78
(c) In this, first we have to calculate the pOH when the concentration of hydroxide ion is, 0.10 M.
[tex]pOH=-\log [OH^-][/tex]
[tex]pOH=-\log (0.10)[/tex]
[tex]pOH=1[/tex]
Now we have to calculate the pH.
[tex]pH+pOH=14\\\\pH=14-pOH\\\\pH=14-1=13[/tex]
The pH of solution is, 13
