Answer:
Speed of one bus is [tex]114 \frac{km}{h}[/tex] and speed of another bus is [tex] 98 \frac{km}{h}[/tex]
Explanation:
Let the speeds of two buses be [tex]v_1\, and\, v_2[/tex] respectively
Since speed of one bus is 16 km/h slower than the other
Therefore [tex]v_1= v_2+16\frac{km}{h}[/tex]
Since buses are traveling in opposite directions so relative speed of buses
[tex]v_{rel}=v_1+v_2= v_2+16\frac{km}{h}+v_2=2v_2+16\frac{km}{h}[/tex]
Distance traveled , [tex]d=v_{rel}t[/tex]
=>[tex]848=4(2v_2+16)[/tex]
=>[tex]v_2=98 \frac{km}{h}[/tex]
[tex]\therefore v_1=v_2+16\frac{km}{h}=(98+16) \frac{km}{h}=114 \frac{km}{h}[/tex]
=>[tex]v_1=114 \frac{km}{h}[/tex]
Thus speed of one bus is [tex]114 \frac{km}{h}[/tex] and speed of another bus is [tex] 98 \frac{km}{h}[/tex]
