Respuesta :
Answer:
The mass of Mg consumed is 23.76 g.
Explanation:
Magnesium and nitrogen react as : three moles of magnesium reacts with one mole of nitrogen to give one mole of magnesium nitride.
as given that the mass of nitrogen reacted = 9.27 g
moles of nitrogen reacted = [tex]\frac{mass}{molarmass}=\frac{9.27}{28}=0.33[/tex]
Thus moles of magnesium reacted = 3 X 0.33 = 0.99 moles
mass of Mg reacted = moles X atomic mass = 0.99 X 24 = 23.76 grams
Mass is the amount of the substance present in the sample of the mixture, it is a quantitative measure. The mass of the magnesium consumed is 23.76 gm.
What is mass?
Mass of any substance is the product of the moles of the substance and the molar mass of the substance present in the sample mixture.
The reaction can be shown as,
[tex]\rm 3 Mg + N_{2} \rightarrow Mg_{3}N_{2}[/tex]
From the reaction the stoichiometry gives,
3 moles of magnesium reacts with 1 mole of nitrogen = 1 mole of magnesium nitride
The mass of the nitrogen reacted is given as 9.27 gm.
Calculate the number of moles of nitrogen:
[tex]\begin{aligned}\rm Moles &=\dfrac{\rm mass}{\rm molar \; mass}\\\\& = \dfrac{9.27}{28}\\\\&= 0.33\;\rm moles\end{aligned}[/tex]
Calculate the moles of magnesium reacted:
[tex]3 \times 0.33 = 0.99 \;\rm moles[/tex]
Calculate the mass of magnesium reacted:
[tex]\begin{aligned} \rm mass &= \rm moles \times molar \; mass\\\\&= 0.99 \times 24\\\\&= 23.76\;\rm gm\end{aligned}[/tex]
Therefore, the mass of magnesium is 23.76 gm.
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