Full Question
Factor 140c + 28 - 14a to identify the equivalent expressions.
Choose 2:
a. 7(20c + 4 - 2a)
b. 2(70c + 28 - 14a)
c. 14(10c + 2 - a)
d. 2(70a + 14 - 7c)
Answer:
a and d
14(10c + 2 - a) and 7(20c + 4 -2a)
Step-by-step explanation:
Given
140c + 28 - 14a
Required
Factorize
To factorize the given expression, we look for a common number that can divide all three individual unit of the expression.
This common number is called common factor
The common factor between them is 14
We then divide each individual unit of the expression with 14.
So, we write 140c + 28 - 14a as
[tex]14(\frac{140c}{14} + \frac{28}{14} -\frac{14a}{14})[/tex]
= 14(10c + 2 - a)
Hence, 14(10c + 2 - a) is equivalent to 140c + 28 - 14a
But the question asks for two results,
So we factorize again
Another common factor between them is 7
We then divide each individual unit of the expression with 7
So, we write 140c + 28 - 14a as
[tex]7(\frac{140c}{7} + \frac{28}{7} -\frac{14a}{7})[/tex]
[tex]= 7(20c + 4 -2a)[/tex]
Hence, 7(20c + 4 -2a) is also equivalent to 140c + 28 - 14a
