Answer:
angle to the incident is 107.09°
Explanation:
Given data
wavelength = 3.14pm = 3.14 ×[tex]10^{-12}[/tex] m
to find out
at what angle to the incident direction scattered
solution
we know that mass of electron that is 9.11 ×[tex]10^{-31}[/tex] kg
and velocity of light is 3 ×[tex]10^{8}[/tex] m/s
and h will be 6.63 ×[tex]10^{-34}[/tex] J-s
so angle will be calculate by formula that is
wavelength = h ( 1- cosθ ) / (mass of electron × velocity of light )
put here all value
3.14 ×[tex]10^{-12}[/tex] = 6.63 ×[tex]10^{-34}[/tex] ( 1- cosθ) / ( 9.11 ×[tex]10^{-31}[/tex] × 3 ×[tex]10^{8}[/tex] )
cosθ = 1 - 1.294
cosθ = -0.294
θ = 107.09°
so angle to the incident is 107.09°
