Answer:
A. [98.6F,105.8F]
B. [170.6F,186.8F]
C. [-23.8F,-7.6F]
D. [219.2F,251.6F]
Step-by-step explanation:
A. 32 to 41 degrees
[tex]F=(\frac{9}{5}*^{o}C)+32[/tex]
Converting 32 [tex]^{o}C[/tex] to Farenheit:
[tex]F=(\frac{9}{5}*32)+32[/tex]
F=98.6F
Converting 41 [tex]^{o}C[/tex] to Farenheit:
[tex]F=(\frac{9}{5}*41)+32[/tex]
F=105.8F
Writing the answer in interval notation : [98.6F,105.8F]
B. 77 to 86 degrees
[tex]F=(\frac{9}{5}*^{o}C)+32[/tex]
Converting 77 [tex]^{o}C[/tex] to Farenheit:
[tex]F=(\frac{9}{5}*77)+32[/tex]
F=170.6F
Converting 86 [tex]^{o}C[/tex] to Farenheit:
[tex]F=(\frac{9}{5}*86)+32[/tex]
F=186.8F
Writing the answer in interval notation : [170.6F,186.8F]
C. -31 to -22 degrees
[tex]F=(\frac{9}{5}*^{o}C)+32[/tex]
Converting -31 [tex]^{o}C[/tex] to Farenheit:
[tex]F=(\frac{9}{5}*-31)+32[/tex]
F=-23.8F
Converting -22 [tex]^{o}C[/tex] to Farenheit:
[tex]F=(\frac{9}{5}*-22)+32[/tex]
F=-7.6F
Writing the answer in interval notation : [-23.8F,-7.6F]
D. 104 to 122 degrees
[tex]F=(\frac{9}{5}*^{o}C)+32[/tex]
Converting 104 [tex]^{o}C[/tex] to Farenheit:
[tex]F=(\frac{9}{5}*104)+32[/tex]
F=219.2F
Converting 122 [tex]^{o}C[/tex] to Farenheit:
[tex]F=(\frac{9}{5}*122)+32[/tex]
F=251.6F
Writing the answer in interval notation : [219.2F,251.6F]
