Respuesta :
We're told that the ODE
[tex]x^2y''-5xy'+8y=24[/tex]
has solution
[tex]y=C_1x^2+C_2x^4+3[/tex]
a. If [tex]y(-1)=0[/tex] and [tex]y(1)=8[/tex], then
[tex]\begin{cases}0=C_1+C_2+3\\8=C_1+C_2+3\end{cases}[/tex]
but there is no solution to this system, so a member cannot be found.
b. If [tex]y(0)=8[/tex] and [tex]y(1)=5[/tex], then
[tex]\begin{cases}8=3\\5=C_1+C_2+3\end{cases}[/tex]
but the first equation is obviously false, so a member cannot be found.
c. If [tex]y(0)=3[/tex] and [tex]y(1)=0[/tex], then
[tex]\begin{cases}3=3\\0=C_1+C_2+3\end{cases}[/tex]
which has infinitely many solutions for [tex]C_1,C_2[/tex], so a member can be found.
d. If [tex]y(1)=3[/tex] and [tex]y(2)=15[/tex], then
[tex]\begin{cases}3=C_1+C_2+3\\15=4C_1+256C_2+3\end{cases}\implies C_1=-\dfrac5{84},C_2=\dfrac5{84}[/tex]
so a member can be found.
By checking all the options and finding number of solution we can say that differential equation [tex]$x^{2} y^{\prime \prime}-5 x y^{\prime}+8 y=24$\\$\\[/tex] Â have a member of the family when y(1)=3 and y(2)=15
What is a differential equation?
An equation of function and their derivatives is called differential equation .
Given differential equation
[tex]$x^{2} y^{\prime \prime}-5 x y^{\prime}+8 y=24$\\$\\[/tex]
And solution of this equation is
[tex]$y=C_{1} x^{2}+C_{2} x^{4}+3$[/tex]
(a)
[tex]y(-1)=0$ \ \ \text{and }\ $y(1)=8$[/tex]
Putting these values in solution
[tex]C_{1}+C_{2}+3 =0 \\ \text{and }C_{1}+C_{2}+3=8[/tex]
Both lines are parallel so there is no solution in this case . Hence a member can not be found
(b)
[tex]y(0)=8$\text{ and } $y(1)=5$[/tex]
Putting these values in solution
[tex]8=3 \\\text{and }C_{1}+C_{2}+3=5[/tex]
Which is not possible so there is no solution in this case .Hence a member can not be found
(c)
[tex]y(0)=3 \ \ \text{and } y(1)=0[/tex]
Putting these values in solution
[tex]3=3 \\C_{1}+C_{2}+3=0[/tex]
These equation have infinitely many solution .Hence infinite member can  be found
(d)
[tex]y(1)=3$ \text{ and } $y(2)=15[/tex]
Putting these values in solution
[tex]C_{1}+C_{2}+3 =3\ \ \ \ \Rightarrow C_{1}+C_{2} =0 \\\\\4 C_{1}+256 C_{2}+3=15 \\\\\Rightarrow 4 C_{1}+256 C_{2}=12 \\\\\Rightarrow C_{1}+64 C_{2}=3 \\[/tex]
as  these system of equation has unique solution .Hence one member can  be found
By checking all the options and finding number of solution we can say that differential equation [tex]$x^{2} y^{\prime \prime}-5 x y^{\prime}+8 y=24$\\$\\[/tex] Â have a member of the family when y(1)=3 and y(2)=15 .
To learn more about  differential equation visit :https://brainly.com/question/1164377