Answer:
Higher frequency
Explanation:
We can imagine a chemical bond between two atoms as if it were two balls connected by a spring.
According to Hooke's Law, the stretching frequency f is
[tex]f = \dfrac{1}{2 \pi}\sqrt{ \dfrac {k}{\mu}}[/tex]
where µ is the reduced mass of the system
[tex]\mu = \dfrac{m_{1} + m_{2}}{m_{1}m_{2} }[/tex]
The strength of the bond is analogous to k, the force constant of the spring. Then,
[tex]f \propto \sqrt{k}[/tex]
Thus, the stronger the bond, the greater the frequency of vibration.
Yes, a strong chemical bond have a higher frequency than a weak bond.
There is direct relation between strength of a bond and its frequency. Stronger bond have higher frequency whereas weaker bond has lower frequency.
Thus, stronger bonds generally vibrate faster than weaker bonds so we can conclude that bonds which are stronger having higher frequencies.
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