Answer:
(1,3)
Step-by-step explanation:
we have
[tex]y> -2[/tex] -----> inequality A
[tex]x+y \leq 4[/tex] -----> inequality B
Remember that
If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequality of the system
Verify each ordered pair
case 1) we have
(-2,-3)
Verify inequality A
[tex]-3> -2[/tex] -----> is not true
therefore
The ordered pair is not a solution of the system of inequalities
case 2) we have
(0,-4)
Verify inequality A
[tex]-4> -2[/tex] -----> is not true
therefore
The ordered pair is not a solution of the system of inequalities
case 3) we have
(1,3)
Verify inequality A
[tex]3> -2[/tex] -----> is true
Verify inequality B
[tex]1+3 \leq 4[/tex]
[tex]4 \leq 4[/tex] -----> is true
therefore
The ordered pair is a solution of the system of inequalities
case 4) we have
(1,5)
Verify inequality A
[tex]5> -2[/tex] -----> is true
Verify inequality B
[tex]1+5 \leq 4[/tex]
[tex]6 \leq 4[/tex] -----> is not true
therefore
The ordered pair is not a solution of the system of inequalities
