Answer:
2Al(s) +3Ni²āŗ(aq) ā¶ 2Al³āŗ(aq) + 3Ni(s) Ā
Explanation:
The unbalanced equation is
Al(s) + Ni²āŗ(aq) ā¶ Ni(s) + Al³āŗ(aq)
(i) Half-reactions
Al(s) ā¶ Al³āŗ(aq) + 3eā»
Ni²āŗ(aq) + 2eā» ā¶ Ni(s)
(ii) Balance charges
2 Ć [Al(s) ā¶ Al³āŗ(aq) + 3eā»]
3 Ć [Ni²āŗ(aq) + 2eā» ā¶ Ni(s)]
gives
2Al(s) ā¶ 2Al³āŗ(aq) + 6eā»
3Ni²āŗ(aq) + 6eā» ā¶ 3Ni(s)
(iii) Add equations
2Al(s) ā¶ 2Al³āŗ(aq) + 6eā»
3Ni²āŗ(aq) + 6eā» ā¶ 3Ni(s) Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā
2Al(s) +3Ni²āŗ(aq) + 6eā» ā¶ 2Al³āŗ(aq) + 3Ni(s) + 6eā»
Simplify (cancel electrons)
2Al(s) +3Ni²āŗ(aq) ā¶ 2Al³āŗ(aq) + 3Ni(s)