Answer:
64.11% for 200 days.
t=67.74 days for R=95%.
t=97.2 days for R=90%.
Explanation:
Given that
β=2
Characteristics life(scale parameter α)=300 days
We know that Reliability function for Weibull distribution is given as follows
[tex]R(t)=e^{-\left(\dfrac{t}{\alpha}\right)^\beta}[/tex]
Given that t= 200 days
[tex]R(200)=e^{-\left(\dfrac{200}{300}\right)^2}[/tex]
R(200)=0.6411
So the reliability at 200 days 64.11%.
When R=95 %
[tex]0.95=e^{-\left(\dfrac{t}{300}\right)^2}[/tex]
by solving above equation t=67.74 days
When R=90 %
[tex]0.90=e^{-\left(\dfrac{t}{300}\right)^2}[/tex]
by solving above equation t=97.2 days
