Answer:
[tex]- 10[/tex] cm
Explanation:
[tex]h_{o}[/tex] = height of the object = 2 cm
[tex]h_{i}[/tex] = height of the image
[tex]d_{o}[/tex] = distance of the object from the mirror = 30 cm
[tex]f[/tex] = focal length of the mirror = 25 cm
[tex]d_{i}[/tex] = image distance
using the mirror equation
[tex]\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}[/tex]
[tex]\frac{1}{30} + \frac{1}{d_{i}} = \frac{1}{25}[/tex]
[tex]d_{i} = 150[/tex] cm
using the equation
[tex]\frac{h_{i}}{h_{o}} = \frac{- d_{i}}{d_{o}}[/tex]
[tex]\frac{h_{i}}{2} = \frac{- 150}{30}[/tex]
[tex]h_{i} = - 10[/tex] cm
