Answer:
49.24 °C
Explanation:
R₀ = Resistance of the silver wire at 20.0 °C, = 4.50 Ω
T₀ = initial temperature of the silver wire = 20.0 °C
R = Resistance of the silver wire at temperature "T" = 5 Ω
T = Final temperature of silver wire
α = Temperature coefficient of resistance = 0.0038 °C
Using the equation
R = R₀ (1 + α (T - T₀))
Inserting the values
5 = (4.50) (1 + (0.0038) (T - 20))
T = 49.24 °C
